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A black body emits maximum radiation of ...

A black body emits maximum radiation of wavelength `lambda_(1)` at a certain temperature `T_(1)`. On increasing the temperature, the total energy of radiation emitted is increased 16 times at temperature `T_(2)`. If `lambda_(2)` is the wavelength corresponding to which maximum radiation is emitted at temperature `T_(2)`. Calculate the value of `((lambda_(1))/(lambda_(2)))`.

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The correct Answer is:
`lambda_1/lambda_2=2`
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