Home
Class 12
PHYSICS
The separation between the plates of a p...

The separation between the plates of a parallel plate capacitor , connected to a battery (zero resistance) of constant EMF is increased with constant (very slow) speed by external forces . During the process, w is the work done dy external forces. `DeltaU` is the change in potential energy of the capacitor , `w_b` is work done by the battery and H is the heat loss in the circuit . Then

A

`W+W_b=DeltaU`

B

`H ne 0`

C

`H=DeltaU`

D

`W=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Force of attraction between the plates of a parallel plate capacitor is

The separation between the plates of a charged parallel-plate capacitor is increased. The force between the plates

The work done by the external forces on a system equals the change in

If initial charge on all the capacitors were zero , work done by the battery in the circuit shown is

A compass needle is placed in the gap of a parallel plate capacitor. The capacitor is connected to a battery through a resistance. The compass needle

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

An uncharged capacitor is fully charged with a battery . The ratio of energy stored in the capacitor to the work done by the battery in this process is

A parallel-plate capacitor is connected to a battery. A metal sheet of negligible thickness is placed between the plates. The sheet remains parallel to the plates of the capacitor.