Home
Class 12
PHYSICS
A conducting rod of length 1m aligned al...

A conducting rod of length `1m` aligned along the unit vector `((3)/(5)hatj+(4)/(5)hatj`), is moving with a velocity `vecv=(2hati)m//s`. The motion take place in a uniform magnetic field `vecB=(hatj-2hatk)`tesla. Find the magnitude of induced emf in across the rod in volt.

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Similar Questions

Explore conceptually related problems

A charge q moves with a velocity 2m//s along x- axis in a unifrom magnetic field B=(hati+2hatj+3hatk) tesla.

A proton is projected with velocity vecV=2hati in a regionn where magnetic field vecB=(hati+3hatj+4hatk)muT and electric field vecE=10hatimuV//m . Then find out the net acceleration of proton:

1 micro C charge moves with the velocity vecv=4hati+6hatj+3hatk in uniform magnetic field, vecB= 3hati+4hatj-3hatk xx 10^(-3). Force experience by charged particle in units of 10^(-9) N will be,

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

Find the resultant of vectors veca=hati-hatj+2hatk and vecb=hati+2hatj-4hatk . Find the unit vector in the direction of the resultant vector.

A conducting rod of unit length moves with a velocity of 5m/s in a direction perpendicular to its length and perpendicular to a uniform magnetic field of magnitude 0.4T . Find the emf induced between the ends of the stick.

In a magnetic field vecB=hati+yhatj+3hatk a charge particle (q, m) is moving with velocity vecV=2hati+3hatj+zhatk experiences a force vecF=-hati+2hatj+hatk . The value of y and z may be

An electric charge +q moves with velocity vecv=3hati+4hatj+hatk ,in an electromagnetic field given by: vecE=3hati+hatj+2hatk and vecB=hati+hatj+3hatk .The y -component of the force experienced by +q is: