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a prism of refractive index sqrt2 refrac...

a prism of refractive index `sqrt2` refracting angle A produces minimum deviation `D_m` of a ray on one face at an angle of incidence `45^@` . The values of A and `D_m` are respectively.

A

`45^@,45^@`

B

`45^@,60^@`

C

`60^@,30^@`

D

`60^@,45^@`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the refracting angle \( A \) of the prism and the minimum deviation \( D_m \) when a ray of light passes through the prism at an angle of incidence of \( 45^\circ \) and the refractive index \( \mu \) of the prism is \( \sqrt{2} \). ### Step-by-Step Solution: 1. **Understanding the Minimum Deviation Condition**: - At minimum deviation, the angle of incidence \( I \) is equal to the angle of emergence \( E \). - Therefore, we have \( I = E \). 2. **Using the Prism Formula**: - The relationship between the angles in a prism is given by: \[ A = r_1 + r_2 \] - At minimum deviation, \( r_1 = r_2 = \frac{A}{2} \). - Thus, we can rewrite the equation as: \[ A = 2r_1 \] 3. **Applying Snell's Law**: - According to Snell's Law: \[ \mu_1 \sin I = \mu_2 \sin r \] - Here, \( \mu_1 = 1 \) (refractive index of air), \( \mu_2 = \sqrt{2} \), \( I = 45^\circ \), and \( r = r_1 \). - Plugging in these values: \[ 1 \cdot \sin(45^\circ) = \sqrt{2} \cdot \sin(r_1) \] - Since \( \sin(45^\circ) = \frac{1}{\sqrt{2}} \), we have: \[ \frac{1}{\sqrt{2}} = \sqrt{2} \cdot \sin(r_1) \] 4. **Solving for \( r_1 \)**: - Rearranging the equation gives: \[ \sin(r_1) = \frac{1}{2} \] - Therefore, \( r_1 = \sin^{-1}\left(\frac{1}{2}\right) = 30^\circ \). 5. **Finding the Angle of Prism \( A \)**: - Now substituting \( r_1 \) back into the equation for \( A \): \[ A = 2r_1 = 2 \times 30^\circ = 60^\circ \] 6. **Calculating Minimum Deviation \( D_m \)**: - The formula for the deviation \( D \) in a prism is: \[ D = I + E - A \] - For minimum deviation, since \( I = E \): \[ D_m = 2I - A \] - Substituting \( I = 45^\circ \) and \( A = 60^\circ \): \[ D_m = 2 \times 45^\circ - 60^\circ = 90^\circ - 60^\circ = 30^\circ \] ### Final Answers: - The refracting angle \( A \) is \( 60^\circ \). - The minimum deviation \( D_m \) is \( 30^\circ \).
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