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In a Young's double slit experiment, fi...

In a Young's double slit experiment, films of thickness `t_(A)` and `t_(B)` and refcative indices `mu_(A)` and `mu_(B)` are placed in front of slits A and B respectively. If `mu_(A)t_(A)=mu_(B)t_(B)`, then the central maxima may

A

not shift

B

shift towards A if `t_A lt t_B`

C

shift towards B if `t_Alt t_B`

D

shift towards A if `t_A gt t_B`

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To solve the problem, we need to analyze the situation in a Young's double slit experiment with films of different thicknesses and refractive indices placed in front of the slits. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two slits A and B, with films of thickness \( t_A \) and \( t_B \) and refractive indices \( \mu_A \) and \( \mu_B \) placed in front of each slit respectively. 2. **Path Difference Calculation**: - The optical path length for light passing through a medium is given by the product of the refractive index and the thickness of the medium. - For slit A, the optical path length is \( x_1 = t_A \mu_A \). - For slit B, the optical path length is \( x_2 = t_B \mu_B \). 3. **Calculating the Shift**: - The shift due to the films in front of the slits is given by: \[ x = (t_A \mu_A - t_B \mu_B) + (t_B - t_A) \] - This can be simplified to: \[ x = (t_A \mu_A - t_B \mu_B) + t_B - t_A \] 4. **Using the Given Condition**: - We are given that \( \mu_A t_A = \mu_B t_B \). - This implies that \( t_A \mu_A - t_B \mu_B = 0 \). - Therefore, substituting this into our equation for the shift: \[ x = 0 + (t_B - t_A) = t_B - t_A \] 5. **Analyzing the Shift**: - If \( t_B = t_A \), then \( x = 0 \); the central maxima does not shift. - If \( t_B > t_A \), then \( x > 0 \); the central maxima shifts towards slit A. - If \( t_B < t_A \), then \( x < 0 \); the central maxima shifts towards slit B. ### Conclusion: - The central maxima will not shift if \( t_B = t_A \). - The central maxima will shift towards A if \( t_B > t_A \). - The central maxima will shift towards B if \( t_B < t_A \). ### Final Answer: - The correct options are: - Central maxima does not shift if \( t_B = t_A \). - Central maxima shifts towards A if \( t_B > t_A \). - Central maxima shifts towards B if \( t_B < t_A \).
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