Home
Class 12
PHYSICS
A satellite of mass m is revolving aroun...

A satellite of mass m is revolving around the Earth at a height R above the surface of the Earth. If g is the gravitational intensity at the Earth’s surface and R is the radius of the Earth, then the kinetic energy of the satellite will be:

A

`mgR//2`

B

mgR/4

C

mgR

D

mgR/6

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R :-

The height above the surface of earth at which the gravitational filed intensity is reduced to 1% of its value on the surface of earth is

A satellite of mass m_0 is revolving around the earth in circular orbit at a height of 3R from surface of the earth the areal velocity of satellite is (where R is radius of earth and M_0 is the mass of earth)

The potential energy of a satellite of mass m revolving at height R above the surface of the earth where R= radius of earth is

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

A satellite of mass m revolves around the earth of radius R at a hight x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

A man weighs 'W' on the surface of the earth and his weight at a height 'R' from surface of the earth is ( R is Radius of the earth )

Two satellites of same mass are orbiting round the earth at heights of r_1 and r_2 from the centre of earth. Their kinetic energies are in the ratio of :

Two identical satellites A and B revolve round the earth in circular orbits at distance R and 3R from the surface of the earth. The ratio of the linear momenta of A and B is (R = radius of the earth)

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)