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In a Young's double slit experiment, the...

In a Young's double slit experiment, the light sources is at distance `l_1 = 20mu m ` and `l_2 = 40 mu m` form the main slit. The light of wavelength lambda = 500nm is incident on slits separated at a distance `10mu m `. A screen is placed at a distance D = 2 away from the slits as shown in figure. Find
(a) the values of `theta` relative to the central line where maxima appear on the screen?
(b) how many maxima will appear on the screen?
(c) what should be the minimum thickness of a slab of refractive index 1.5 placed on the path of one of the ray so that minima occurs at C ?
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Text Solution

Verified by Experts

`sin theta=2 [n/(40)-1], "Hence" theta= sin ^(-1)[2(n/(40)-1)]`, (b) 40, (c ) 500nm
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