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Weight of a body of mass m decreases by ...

Weight of a body of mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is:

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`vec(F)=(m(vec(v)_(2)-vec(v)_(1)))/(delta t)`
where `|vec(v)_(2)-vec(v)_(1)|=v_(2)+v_(1)`, where `v_(1)=sqrt(2gh_(1))` and `v_(2)=sqrt(2gh_(2))` `rArr F=(m(sqrt(2gh_(1))+sqrt(2gh_(2))))/(delta t)`
`=(1)/(10)[(sqrt(2(9.8)(2.5))+sqrt(2(9.8)(0.625)))/(0.01)]=105 N`
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