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A bomb of mass m is thrown with velocity...

A bomb of mass m is thrown with velocity v. It explodes and breaks into two fragments. One fragment of mass m', immediately after the explosion, comes to rest. The speed of the other fragment will be

A

`(mv)/(m-m')`

B

`(mv)/(m')`

C

v

D

`(mv)/(m+m')`

Text Solution

AI Generated Solution

To solve the problem, we will apply the principle of conservation of linear momentum. Here's the step-by-step solution: ### Step 1: Understand the initial conditions A bomb of mass \( m \) is thrown with an initial velocity \( v \). Before the explosion, the total momentum of the system is given by: \[ \text{Initial Momentum} = m \cdot v \] ...
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