Centre of mass is at point X (1,1,1) when system consists of particles of masses 2, 3, 4 and 5 kg. If the centre of mass shifts to point Y (2, 2, 2) on removal of the mass of 5 kg. What was its position ?

Explanation

To find the position of the 5 kg mass when the center of mass shifts from point X (1, 1, 1) to point Y (2, 2, 2) upon its removal, we can follow these steps:

### Step 1: Understand the Center of Mass Formula
The center of mass (CM) of a system of particles is given by the formula:
\[ \text{CM} = \frac{m_1 \vec{r_1} + m_2 \vec{r_2} + m_3 \vec{r_3} + \ldots}{m_1 + m_2 + m_3 + \ldots} \]
where \( m_i \) is the mass of each particle and \( \vec{r_i} \) is the position vector of each particle.
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