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If u(1), u(2) and v(1), v(2) are the ini...

If `u_(1), u_(2)` and `v_(1), v_(2)` are the initial and final velocities of two particles before and after collision respectively, then `(v_(2)-v_(1))/(u_(1)-u_(2))` is called ___________.

A

(A)Friction

B

(B)Coefficient of restitution

C

(C) Electrostatic force

D

(D) Gravitation

Text Solution

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The correct Answer is:
To solve the question, we need to define the term given in the expression \((v_2 - v_1) / (u_1 - u_2)\) in the context of collisions between two particles. ### Step-by-Step Solution: 1. **Understanding the Variables**: - Let \(u_1\) and \(u_2\) be the initial velocities of the two particles before the collision. - Let \(v_1\) and \(v_2\) be the final velocities of the two particles after the collision. 2. **Defining Velocity of Separation and Velocity of Approach**: - The **velocity of separation** after the collision is defined as the difference in final velocities: \[ \text{Velocity of Separation} = v_2 - v_1 \] - The **velocity of approach** before the collision is defined as the difference in initial velocities: \[ \text{Velocity of Approach} = u_1 - u_2 \] 3. **Coefficient of Restitution**: - The **coefficient of restitution (e)** is a measure of how elastic a collision is. It is defined as the ratio of the velocity of separation to the velocity of approach: \[ e = \frac{\text{Velocity of Separation}}{\text{Velocity of Approach}} = \frac{v_2 - v_1}{u_1 - u_2} \] 4. **Identifying the Answer**: - From the definition, we can see that the expression \((v_2 - v_1) / (u_1 - u_2)\) is indeed the coefficient of restitution. - Therefore, the blank in the question can be filled with **coefficient of restitution**. ### Final Answer: The answer is **coefficient of restitution**. ---
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