Home
Class 12
PHYSICS
A ball of mass m is projected vertically...

A ball of mass m is projected vertically up from a smooth horizontal floor with a speed v. Find the total momentum delivered by the ball to the surface during impact assuming e as the cofficient of restitution of impact.

Text Solution

Verified by Experts

The correct Answer is:
`mv_(0)((1+e)/(1-e))`
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball of mass m=1kg strikes a smooth horizontal floor as shown in figure. The impulse exerted on the floor is

A ball is thrown onto a smooth floor with speed u at angle theta = 45^(@) . If it rebounds with a speed v at the same angle phi = 45^(@) . Then the coefficient of restitution is

A ball of mass m moving with speed u collides with a smooth horizontal surface at angle theta with it as shown in figure. The magnitude of impulse imparted to surface by ball is [Coefficient of restitution of collision is e]

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A ball of mass 1 kg drops vertically on to the floor wit a speed of 25 m//s . It rebounds with an initial velocity of 10 m//s . What impulse acts on the ball during contact ?

A ball falls vertically onto a floor with momentum p and then bounces repeatedly. If coefficient of restitution is e , then the total momentum imparted by the ball to the floor is

A ball moving with speed v collides with a horizontal smooth surface at an angle theta with normal to surface as shown in figure. If coefficient of restitution of collision is e, then find v'

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A wedge of mass M and angle alpha rests on a smooth horizontal plane. A smooth sphere of mass m strickes it in a direction perpendicular to its inclined face and rebounds. If the coefficient of restitution is e, find the ratio of the speed of the sphere just before and just after the impact.

A smooth ball of mass m is suspended from a light string of length 1 m . Another ball of mass 2m strikes the ball of mass in horizontally with a speed of u=sqrt(35)m//s . The coefficient of restitution for the collision is e . The string becomes loose, when it makes an angle of 30^(@) with the horizontal, find the value of e .