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A particle of mass m strikes a horizonta...

A particle of mass `m` strikes a horizontal smooth floor with velocity `u` making an angle `theta` with the floor and rebound with velocity `v` making an angle `theta` with the floor. The coefficient of restitution between the particle and the floor is `e`. Then

A

The impulse delivered by the floor to the body is mu (1 + e) sin `theta`.

B

`tan phi = e tan theta`

C

`v=u sqrt(1-(1-(1-e^(2))sin^(2)theta)`

D

the ratio of final K.E. to initial K.E. is `(cos^(2)theta+e^(2)sin^(2)theta)`

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The correct Answer is:
A, B, C, D
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