Home
Class 12
PHYSICS
A cricket ball of mass 200 gm moving wit...

A cricket ball of mass 200 gm moving with velocity 15 m/s is brought to rest by a player in 0.05 sec. What is the impulse of the ball and average force exerted by player ?

Text Solution

Verified by Experts

Impulse = change in momentum `=m(v-u)=0.2(0-15)= -3Ns`
Average force = Impulse/Time `=(3)/(0.05)=60N`
Promotional Banner

Similar Questions

Explore conceptually related problems

A cricket ball of mass 100 g moving with a speed of 30 "ms"^(-1) is brought to rest by a player in 0.03 s. Find the change in momentum of ball.

A cricket ball of mass 100 g moving with a speed of 30 "ms"^(-1) is brought to rest by a player in 0.03 s. Find the average force applied by the player.

A cricket ball of mass 150 g moving at a speed of 25 m s^(-1) is brought to rest by a player in 0.03 s. Find the average force applied by the player.

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A ball of mass m, travelling with velocity 2hati+3hatj receives an impulse -3mhati . What is the velocity of the ball immediately afterwards?

A cricket ball of mass 150 kg is moving with a velocity of 12 m//s and is hit by a bat so that ball is turned back with a velocity of 20 m//s . The force of the blow acts for 0.01 s on the ball . Find the average force exerted by the bat on the ball.

A player caught a cricket ball of mass 150g moving at a rate of 20m//s . If the catching process is completed in 0.1s, the force of the blow exerted by the ball on the hand of the player is equal to

A player takes 0.1s I catching a ball of mass 150 g moving with velocity of 20 m/s. The force imparted by the bal on the hands of the player is

A ball of mass 2 kg is moving with velocity 20 m/sec strikes with the surface and rebounds with same speed, if time of contact is 0.1 sec then calculate average force on the ball.