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A uniform chain of mass m and length I ...

A uniform chain of mass m and length I is kept on the table with a part of it overhanging (see figure). If the coefficient of friction between the table and the chain is `1//3` then find the maximum length of the chain that can overhang such that the chain remain in equilibrium.

A

`L//3`

B

`L//2`

C

`L//4`

D

`2L//3`

Text Solution

Verified by Experts

The correct Answer is:
C


Let x be the length of the overhanging part
`f_(r)=mu[(m)/(L)(L-x)g]`
`T=f_(r)`
`T=(m)/(L)xxg`
`rArr mu((m)/(L))(L-x)g=(m)/(L) g x`
`rArr (1)/(3)(L-x)=x rArr x =(L)/(4)`
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