In the shown figure the tension in the horizontal cord is 30N. Find the weight of the body B.

Explanation

(i) isolate the point P
(ii) The forces acting on it are:
Unknown tension `T_(2)` in cord 2
Unknown tension `T_(1)` in cord 1.
Known tension of 30N in the horizontal cord.
(iii) `T_(2)` is resolved along x and y axes.
(iv) Condition of equilibrium:
`SigmaF_(x)=0 rArr 30-T_(2) sin 45^(@)=0 " " (1)`
and `Sigma F_(y)=0 rArr T_(2) cos 45^(@)-T_(1)=0 " " (2)`
Since body B is also in equilibrium,
Hence `T_(1)=W" " (3)`
(v) After solving these equations,
we get `W=30N`