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Three forces are acting on a particle of...

Three forces are acting on a particle of mass m intially in equilibrium. If the first two forces `(R_(1) and R_(2))` are perpendicular to each other and suddenly the third force `(R_(3))` is removed, then the acceleration on the particle is

A

`(F_(1))/(m)`

B

`(F_(2)F_(3))/(mF_(1))`

C

`((F_(2)-F_(3)))/(m)`

D

`(F_(2))/(m)`

Text Solution

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The correct Answer is:
A
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