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Two bodies M and N of equal masses are s...

Two bodies M and N of equal masses are suspended from two separate massless springs of spring constants `k_(1)` and `k_(2)` respectively . If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of M to that on N is

A

`(k_(2))/(k_(1))`

B

`sqrt((k_(2))/(k_(1)))`

C

`(k_(1))/(2)`

D

`sqrt((k_(1))/(k_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_("max 1") = v_("max 2")`
`rArr omega_(1) A_(1) = omega_(2) A_(2)`
`rArr sqrt((k_(1))/(m)) A_(1) = sqrt((k_(2))/(m)) A_(2)`
`rArr (A_(1))/(A_(2)) = sqrt((k_(2))/(k_(1)))`
Hence (B) is correct
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