A particle of mass 4g performs S.H.M. between `x = -10 cm and x = + 10` cm along x-axis with frequency 60Hz, initially the particle is at x = +5 cm. Find
velocity-displacement and acceleration displacement curve of this motion.

A particle executes SHM with an amplitude 8 cm and a frequency 4 Hz initially, in the positive direction , determine its displacement equation and the maximum velocity and acceleration.

The equation of S.H.M. of a particle is a+4pi^(2)x=0 , where a is instantaneous linear acceleration at displacement x. Then the frequency of motion is

The displacement of a particle along the x-axis is given by x=3+8t+7t^2 . Obtain its velocity and acceleration at t=2s .

A particle executes SHM with an amplitude of 10 cm and frequency 2 Hz , at t = 0 , the particle is at point where potential energy and kinetic energy are same. Find the equation of displacement of particle.

The velocity of any particle is related with its displacement As, x = sqrt(v+1) , Calculate acceleration at x = 5m .

A particle moves along the x-axis obeying the equation x=t(t-1)(t-2) , where x is in meter and t is in second a. Find the initial velocity of the particle. b. Find the initial acceleration of the particle. c. Find the time when the displacement of the particle is zero. d. Find the displacement when the velocity of the particle is zero. e. Find the acceleration of the particle when its velocity is zero.

The force of a particle of mass 1 kg is depends on displacement as F = —4x then the frequency of S.H.M. is

The acceleration - time graph for a particle moving along x - axis is shown in figure, If the initial velocity of particle is -5m//s , the velocity at t = 8 s is

A particle executes shm with an amplitude of 10 cm and a period of 5 s. Find the velocity and acceleration of the particle of a distance 5 cm from the equilibrium position.

A body of mass 8 kg performs S.H.M. of amplitude 60 cm. The restoring force is 120 N, when the displacement is 60 cm. The time period is