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A second's clock with a iron pendulum is...

A second's clock with a iron pendulum is constructed so a to keep correct time at `10^(@)C`. Give `alpha_("iron")=12xx10^(-6)` per`""^(@)C`. What will be the change in the rate when the temperature rises to `25^(@)C`?

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To solve the problem, we need to determine the change in the rate of a pendulum clock when the temperature rises from 10°C to 25°C, given the coefficient of linear expansion for iron. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Initial temperature, \( T_1 = 10^\circ C \) - Final temperature, \( T_2 = 25^\circ C \) - Coefficient of linear expansion for iron, \( \alpha = 12 \times 10^{-6} \, \text{per} \, ^\circ C \) ...
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