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3000 J of heat is given to a gas at a co...

3000 J of heat is given to a gas at a constant pressure of `2xx10^(5)N//m^(2)`.If its volume increase bny 10 litres during the process find the change in the intrnal energy of the gas.

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To solve the problem, we will use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W). ### Step-by-Step Solution: 1. **Identify the given values**: - Heat added to the gas (Q) = 3000 J - Pressure (P) = 2 × 10^5 N/m² - Volume change (ΔV) = 10 liters = 10 × 10^(-3) m³ = 0.01 m³ (since 1 liter = 0.001 m³) ...
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