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A room heater is made up of thin wall tu...

A room heater is made up of thin wall tubes of copper, each 1.0 m long and 4.0 cm in diameter. Hot water aet `77^(@)C` circulates constantlyh through the tubes. Calculate the amount of heat radiated per second in a room where the average temperature is `27^(@)C`. The emissivity of copper =0.8 and Stefan's contant `=5.67xx10^(-8)Wm^(-2)K^(-1)`

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To solve the problem of calculating the amount of heat radiated per second by the copper tubes of the room heater, we will follow these steps: ### Step 1: Identify the given values - Length of the tube (L) = 1.0 m - Diameter of the tube = 4.0 cm → Radius (r) = 4.0 cm / 2 = 2.0 cm = 0.02 m - Temperature of hot water (T₁) = 77°C = 77 + 273 = 350 K - Average temperature of the room (T₀) = 27°C = 27 + 273 = 300 K - Emissivity of copper (ε) = 0.8 ...
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