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A body cools from 62^(@)C to 50^(@)C in ...

A body cools from `62^(@)C` to `50^(@)C` in 10 minutes and to `42^(@)C` in the next 10 minutes. Find the temperature of surroundings.

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To find the temperature of the surroundings (T₀) given the cooling of a body, we can use Newton's Law of Cooling. The steps to solve the problem are as follows: ### Step 1: Set up the equations based on the cooling data. We know that the body cools from 62°C to 50°C in the first 10 minutes, and then from 50°C to 42°C in the next 10 minutes. Using Newton's Law of Cooling, we can write the equations for the two intervals: 1. For the first 10 minutes: ...
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