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The average translational energy and the...

The average translational energy and the rms speed of molecules in a sample of oxygen gas at `300K` are `6.21xx10^(-21)J` and `484m//s`, respectively. The corresponding values at `600K` are nearly (assuming ideal gas behaviour)

A

`12.42xx10^(-21)` , 968 m/s

B

`6.21xx10^(-21)J,968` m/s

C

`8.78xx10^(-12)J, 684` m/s

D

`12.42xx10^(-21)J, 684` m/s

Text Solution

Verified by Experts

`KE=3/2 kT`
`v_(rms)=sqrt((3RT)/M)`
ie. `(KE_(2))/(KE_(1))=(T_(2))/(T_(1))=2`
`KE_(2)=2KE_(1)=2xx6.21xx10^(-21)=12.42xx10^(-21)J`
`(v_(rms,2))/(v_(rms,1))=sqrt((T_(2))/(T_(1)))=sqrt(2)`
`:.v_(rms,2)=sqrt(2)xxv_(rms,1)=684` m/s
Hence d is correct
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