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A gaseous mixture enclosed in a vessel o...

A gaseous mixture enclosed in a vessel of volume `V` consists of one mole of gas `A` with `gamma = (C_(P))/(C_(V)) = (5)/(3)`an another gas `B` with `gamma = (7)/(5)` at a certain temperature `T`. The gram molecular weights of the gases `A` and `B` are `4` and `32` respectively. The gases `A` and `B` do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation `PV^(19//13)` = constant , in adiabatic process. Find the number of moles of the gas `B` in the gaseous mixture.

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The correct Answer is:
a. 2 gm mole b. 400 .7 m/s c. 0.175 d. `2.487xx10^(-3)V//T`
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