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An iron rod of 0.2cm^(2) cross sectiona ...

An iron rod of `0.2cm^(2)` cross sectiona area is subjected to a manetising field of `1200A-m^(-1)`. The susceptibility of iron is 599. The magnetic flux produced is

A

`0.904 xx 10^(5)` Wb

B

`1.81 xx 10^(-5)` Wb

C

`2.34 xx 10^(-5)` Wb

D

`5.43 xx 10^(-5)` Wb

Text Solution

Verified by Experts

The correct Answer is:
B
`mu = mu_(0) (1+ x) = 4 pi xx 10^(-7) xx 600 = 7.5 xx 10^(-4)`
`B = muH = 7.5 xx 10^(-4) xx 1200 = 0.9`
Hence flux, `phi = 0.9 xx 0.2xx 10^(-4)`
` = 1.8 xx 10^(-6) `Wb
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