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A magnet of magnetic moment 20 A - m^...

A magnet of magnetic moment 20 `A - m^(2)` is freely suspended is a uniform magnetic field of strength 6 T . Work done to rotate it by `60^(@)` will be .

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To solve the problem of calculating the work done to rotate a magnet in a magnetic field, we will follow these steps: ### Step 1: Identify the given values - Magnetic moment (M) = 20 A·m² - Magnetic field strength (B) = 6 T - Initial angle (θ₁) = 0° (the magnet is initially aligned with the magnetic field) - Final angle (θ₂) = 60° (the angle to which the magnet is rotated) ...
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