An iron bar of permeability `8.2 xx 10^(-3)` Wb/A-m is placed in a magentic field of strongth 150 A/m . what is induction in the iron rod ?

Answer

To find the magnetic induction (B) in the iron rod, we can use the relationship between magnetic induction, permeability (μ), and magnetic field strength (H). The formula is given by:

\[ B = \mu H \]

### Step-by-Step Solution:

**Step 1: Identify the given values.**
- Permeability of the iron bar, \( \mu = 8.2 \times 10^{-3} \, \text{Wb/A-m} \)
- Magnetic field strength, \( H = 150 \, \text{A/m} \)

**Step 2: Substitute the values into the formula.**
Using the formula \( B = \mu H \):

\[ B = (8.2 \times 10^{-3} \, \text{Wb/A-m}) \times (150 \, \text{A/m}) \]

**Step 3: Perform the multiplication.**
Calculating the product:

\[ B = 8.2 \times 150 \times 10^{-3} \]

Calculating \( 8.2 \times 150 \):

\[ 8.2 \times 150 = 1230 \]

So,

\[ B = 1230 \times 10^{-3} \, \text{Wb/m}^2 \]

**Step 4: Convert to standard form.**
This can be expressed as:

\[ B = 1.23 \, \text{Wb/m}^2 \]

### Final Answer:
The magnetic induction in the iron rod is:

\[ B = 1.23 \, \text{Wb/m}^2 \]

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