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The magnet of a vibration magnetometer i...

The magnet of a vibration magnetometer is heated so as to reduce its magnetic moment by `19%`. By doing this the period time of the magnetometer will

A

increase by 11%

B

decrease by 19%

C

increase by 19%

D

decrease by 11%

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze how the magnetic moment of a vibration magnetometer affects its time period when the magnetic moment is reduced by 19%. ### Step-by-Step Solution: 1. **Understanding the Formula**: The time period \( T \) of a vibration magnetometer is given by the formula: \[ T = 2\pi \sqrt{\frac{I}{MB}} \] where \( I \) is the moment of inertia, \( M \) is the magnetic moment, and \( B \) is the magnetic field. For our analysis, we will focus on the relationship between the time period and the magnetic moment. 2. **Inversely Proportional Relationship**: From the formula, we can see that the time period \( T \) is inversely proportional to the magnetic moment \( M \). This means that if the magnetic moment decreases, the time period increases. 3. **Calculating the New Magnetic Moment**: The problem states that the magnetic moment is reduced by 19%. If we assume the initial magnetic moment \( M \) is 100 (for simplicity), the new magnetic moment \( M' \) after the reduction will be: \[ M' = M - 0.19M = 100 - 19 = 81 \] 4. **Setting Up the Ratio of Time Periods**: The ratio of the original time period \( T \) to the new time period \( T' \) can be expressed as: \[ \frac{T}{T'} = \sqrt{\frac{M'}{M}} = \sqrt{\frac{81}{100}} = \sqrt{0.81} = \frac{9}{10} \] 5. **Finding the New Time Period**: Rearranging the ratio gives us: \[ T' = \frac{10}{9} T \] This indicates that the new time period \( T' \) is greater than the original time period \( T \). 6. **Calculating the Percentage Increase**: To find the percentage increase in the time period: \[ \text{Percentage Increase} = \left( \frac{T' - T}{T} \right) \times 100 = \left( \frac{\frac{10}{9}T - T}{T} \right) \times 100 = \left( \frac{10 - 9}{9} \right) \times 100 = \frac{1}{9} \times 100 \approx 11.11\% \] Therefore, the time period increases by approximately 11%. 7. **Conclusion**: The time period of the magnetometer will increase by approximately 11%. ### Final Answer: The time period of the magnetometer will increase by 11%.
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