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A moving coil galvanometer has 100 tur...

A moving coil galvanometer has 100 turns and each turns as area of `2cm^(20`. The magnetic field produced by the magent is 0.01T. The diflection in the galvanometer coil is 0.5 rad when a current of 10 mA is passed thorugh it Find the torsional constant of the spiral spring

Text Solution

Verified by Experts

We have `I = (K)/(NAB) = theta`
`implies K = (NABi)/(theta)`
or `K = (100 xx 2 xx 10^(-4) xx 0.01 xx 10 xx 10^(-3))/(0.05)`
or `K = 4.0 xx 10^(-5)` N-m/radian
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