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Two circular coils of radii 10 cm and 40...

Two circular coils of radii 10 cm and 40 cm and equal number of turns are connected in series to a battery. The ratio of magnetic fields at their centres is

A

1 : 4

B

4 : 1

C

2 : 1

D

1 : 1

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of magnetic fields at the centers of two circular coils with different radii, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Formula for Magnetic Field**: The magnetic field \( B \) at the center of a circular coil is given by the formula: \[ B = \frac{\mu_0 n I}{2R} \] where: - \( \mu_0 \) is the permeability of free space, - \( n \) is the number of turns per unit length, - \( I \) is the current flowing through the coil, - \( R \) is the radius of the coil. 2. **Define the Parameters for Each Coil**: - For the first coil (radius \( R_1 = 10 \) cm): \[ B_1 = \frac{\mu_0 n I}{2 \times 0.1} = \frac{\mu_0 n I}{0.2} \] - For the second coil (radius \( R_2 = 40 \) cm): \[ B_2 = \frac{\mu_0 n I}{2 \times 0.4} = \frac{\mu_0 n I}{0.8} \] 3. **Calculate the Magnetic Fields**: - For the first coil: \[ B_1 = \frac{\mu_0 n I}{0.2} \] - For the second coil: \[ B_2 = \frac{\mu_0 n I}{0.8} \] 4. **Find the Ratio of the Magnetic Fields**: To find the ratio \( \frac{B_1}{B_2} \): \[ \frac{B_1}{B_2} = \frac{\frac{\mu_0 n I}{0.2}}{\frac{\mu_0 n I}{0.8}} = \frac{0.8}{0.2} = 4 \] 5. **Express the Ratio**: The ratio of the magnetic fields at the centers of the two coils is: \[ \frac{B_1}{B_2} = 4:1 \] ### Final Answer: The ratio of the magnetic fields at the centers of the two coils is \( 4:1 \). ---
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Knowledge Check

  • A circular coil of wire consisting of 100 turns each of radius 9 cm carries a current of 0.4 A. The magnitude of the magnetic field at the centre of coil is [ mu_(0) = 1256 xx 10^(-7) Sl unit]

    A
    `2.4xx 10^(-4)T`
    B
    `3.5xx 10^(-4)T`
    C
    `2.79xx 10^(-4)T`
    D
    `3xx 10^(-4)T`
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