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Shown in the figure is an R-L circuit. J...

Shown in the figure is an `R-L` circuit. Just after the key `(K)` is closed

A

the current in the circuit is zero

B

potential drop across the resistor is zero

C

emf developed across the inductor equals the emf of the battery

D

no heat is dissipated in the circuit

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
If the equilibrium current in the circuit is `i_(0)` current at any time in transient state is given as
`i= i_(0) (1-e^((t)/(tau))) "where" " "tau=(L)/(R)`
Putting t =0 i= 0
`implies` The voltage drop across the inductor is E that oppose the applied emf E
`implies` E. = E numerically .
Since the circuit current is zero the heat loss that is proportional to `i_(0)^(2) R ` will be zero .
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