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A coil of inductance L = 2.0 mu H and...

A coil of inductance `L = 2.0 mu H` and resitance `R = 1.0 Omega` is connected to a source of constant `emf E = 3.0 V`. A resistance `R_(s) = 2.0 Omega` is connected in parallel with the coil. Find the amount of heat generated in the coil after the swich `Sw` is disconnecied. The internal resistance of the source is negligible.

Text Solution

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From decay equation we known `i=i_(0) e^(((R-R_(0)))/(L)t`
Heat generated H =`int i^(2)"Rdt"`
`H = int {i_(0)e^(R+R_(e)t)/(L)}^(2)"Rdt" = i_(0)^(2) R""(L)/(2(R_(0)+R))=(LE^(2))/(2R(R+R_(0)))`
Putting the values H = 3`mu` J
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