Home
Class 12
PHYSICS
Figure shows a square loop 100 turns as ...

Figure shows a square loop 100 turns as area of `2.5 xx 10^(-3) m^(2)` and a resistance of 100 `Omega`. The magnetic field has a magnitude B = 0.40 T . The work done in pulling the loop out of the field slowly and uniformly in `1.0 "s is n" xx 10^(-6)` then n is

Text Solution

Verified by Experts

The side of the square is 1 = `sqrt(2.5xx10^(-3)m^(2))= 0.05` m
As it is uniformly pulled out in 1.0 s the speed of the loop is V = 0.05 m/s The emf induced in the left arm of the loop is
`epsilon = Nv BL = 100 xx(0.05 m//s)xx (0.40T ) xx (0.05m) = 0.1 v `
The current in the loop is `i=(0.1V) /(100 Omega) = 1.0 xx10^(-3)` A
The force on the left arm due to the magnetic field is
`F=iLBN =N(1.0 xx10^(-3)A) (0.05 m ) (0.40t) = 2.0xx 10^(-5)N`
This force is towards left in the figure. To pull the loop uniformly an external force of
`2.0xx10^(-5) N`
`W = (2.0 xx10^(-5) N) xx(0.05 m) = 1.0 xx10^(-6) J`
Promotional Banner

Similar Questions

Explore conceptually related problems

Shows a square loop having 100 turns, an area of 2.5 X10^(-3) m^2 and a resistance of 100 Omega . The magnetic field has a magnitude B =0.40 T. Find the work done in pulling the loop out of the field, slowly and uniformly is 1.0 s.

Figure show a square loop of side 0.5 m and resistance 10Omega . The magnetic field has a magnitude B=1.0T . The work done in pulling the loop out of the field slowly and uniformly in 2.0s is

Figure show a square loop of side 0.5 m and resistance 10Omega . The magnetic field has a magnitude B=1.0T . The work done in pulling the loop out of the field slowly and uniformly in 2.0s is

Figures shows a square loop of side 1m and resistance 1Omega . The magnetic field on left side of line PQ has a magnitude B=1.0T. The work done in pulling the loop out of the field uniformly in 1 s is

The linear loop has an area of 5 xx 10^(-4)m^(2) and a resistance oof 2 Omega . The larger circular loop is fixed and has a radius of 0.1m . Both the loops are concentric and coplanner. The smaller loop is rotated with an angular velocity omegarads^(-1) about its dismeter. The magnetic flux with the smaller loop is

A circular loop of area 0.01 m^(2) carrying a current of 10 A , is held perpendicular to a magnetic field of intensity 0.1 T . The torque acting on the loop is

A wire loop that encloses an area of 20 cm^2 has a resistance of 10 Omega The loop is placed in a magnetic field of 2.4 T with its plane perpendicular to the field . The loop is suddenly removed from the field. How much charge flows past a given point in the wire ?

A uniform magnetic field B exist in a direction perpedicuar to the plane of a square loop made of a metal wire. The wire has diameter of 4 mm and a total length of 30 cm . The magnetic field changes with time at a steady rate dB/dt = 0.032 T s^(-1) . The induced current in the loop is close to (Resistivity of the metal wire is 1.23 xx 10^(-8) Omega m )

A conducing circular loop of area 2.5xx10^(-3)m^(2) and resistance 10Omega is placed perpendicular to a uniform time varying magnetic field B(t)=0.6 sin(50pit)T . What is the net charge (in mC) flowing through the loop during t = 0 and t = 10 ms ?

A rectangular coil having 60 turns and area of 0.4 m^(2) is held at right angles to a uniform magnetic field of flux density 5 xx 10^(-5)T . Calculate the magnetic flux passing through it.