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A photodiode is made froma semiconductor...

A photodiode is made froma semiconductor `In_(0.53) Gu_(0.47)A_(s), with E_(g)=0.73eV`.What is the maximum wavelength which it can detect ?`h=6.63xx10^(-34)J_(s)`

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To find the maximum wavelength that a photodiode can detect, we can use the relationship between energy and wavelength. The energy of a photon is given by the equation: \[ E = \frac{hc}{\lambda} \] Where: - \( E \) is the energy of the photon, - \( h \) is Planck's constant (\( 6.63 \times 10^{-34} \, \text{J s} \)), - \( c \) is the speed of light (\( 3 \times 10^8 \, \text{m/s} \)), ...
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