Fraction of total power carried by side ...

Fraction of total power carried by side bands is given by-

A

`(P_(S))/P_(T)=m^(2)`

B

`(P_(S))/P_(T)=(1)/(m^(2))`

C

`(P_(S))/P_(T)=(2+m^(2))/(m^(2)`

D

`(P_(S))/P_(T)=(m^(2))/(2+m^(2))`

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The correct Answer is:

D

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