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Two beam of lights are incident normally...

Two beam of lights are incident normally on water `(mu = 4//3)`. If the beam 1 passes through a glass `(mu=3//2)` slab of height h as shown in the figure, the time difference for both the beam for reaching the bottom is:

A

Zero

B

`h/6C`

C

`6h/C`

D

`h/6C`

Text Solution

Verified by Experts

The correct Answer is:
D
The refractive index of glass is greater than that of water. Therefore the speed of light in glass is less.than that of water. It is given as
`v=C/n`,where C=`3xx10^(8)m//s`
v=speed of light in a medium of R.I.n
:.The time difference for the rays
`Deltat=t_(1)-t_(2)=h/v_(g)-h/v_(w)=h/(C//n_(g))-h/(C_(w)//n_(w))=h/C n_(g)-n_(w)`
`impliesDeltat=h/C[3/2-4/3]=h/6C`
Hence(D) is correct.
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