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The pressure exerted by 12 g of an ideal...

The pressure exerted by 12 g of an ideal gas at temperature `T^(@)C` in a vessel volume V litre is one atm. When the temperature is increased by `10^(@)C` at the same volume, the pressure increases by . Calculate the temperature T and volume V.
(Molecular weight of the gas = 120)

Text Solution

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Case (I) : Given P= 1 atm, w=12 g, T=(t+273) K, V=V litre.
Case (II) : `T=t+283, P=1+(10)/(100)=1.1` atm
`W=12 g, V=V` litre.
Using equation, PV =nRT
Case (I) : `1xxV=(12)/(m) xx R (t+273)" ….(1)"`
Case (II) `1.1 V =(12)/(m) xx R (t+283)" ....(2)"`
By eq (1) and (2),
`(1.1)/(1)=(t+283)/(t+273)`
`therefore 1.1 t=-17.3, t=-173^(@)C=100 K`
Also from case (I), `1xx v=(12)/(120) xx0.082 xx100`
V=0.82 litre.
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