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Calculate the pressure exerted by 10^(23...

Calculate the pressure exerted by `10^(23)` gas particles each of mass `10^(-22) g` in a container of volume `1 dm^(3)`. The root mean square speed is `10^(5) cm s^(-1)`

Text Solution

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No. of molecules of gas `=10^(23)`
mass of one molecules `=10^(-22) g`
`V=1" litre "=10^(23) cm^(3)`
`U_("rms")=10^(5)` cm/sec
From kinetic equation
`PV =((1)/(3)) mnu^(2)`.
`P xx 1 =((1//3)xx10^(23)xx10^(-22)xx(10^(5))^(2))/(10^(3))`
`therefore P=-3.3xx10^(7)" dyne cm"^(-2)`
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