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127 mL of a certain gas diffuses in the ...

`127 mL` of a certain gas diffuses in the same time as `100 mL` of chlorine under the same conditions. Calculate the molecular weight of the gas.

Text Solution

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If t is the time taken for diffusion of each gas, then by Graham.s law of diffusion
`(r_(x))/(rCl_(2))=(127//t)/(100//t)=sqrt((M_(Cl_(2)))/(M_(x)))=sqrt((71)/(M_(x)))`
Or `(71)/(M_(x))=((127)/(100))^(2)`
or `M_(x) =44 u`
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