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The mass of molecule A is twice the mass...

The mass of molecule A is twice the mass of molecule B. The rms speed of A is twice the rms speed of B. If two samples of A and B contain same no. of molecules, what will be the ratio of P of two samples in separate containers of equal volume.

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To solve the problem, we need to find the ratio of the pressures (P) of two samples of gases A and B, given the conditions about their molecular masses and root mean square (rms) speeds. Here’s a step-by-step solution: ### Step 1: Define the Given Information - Let the mass of molecule B be \( m_B \). - Therefore, the mass of molecule A is \( m_A = 2m_B \). - The rms speed of molecule B is \( v_B \). - Thus, the rms speed of molecule A is \( v_A = 2v_B \). - Both samples contain the same number of molecules. ...
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