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For two gases, A & B with molecular mass...

For two gases, A & B with molecular mass `M_A` and `M_B` it is observed that at a certain temperature T, the mean velocity of A is equal to the root mean square velocity of B. Thus, the mean velocity of A can be made equal to the mean velocity of B if

A

A is at temperature T and B at T', `T gt T'`

B

A is lowered to a temperature `T_(2), T_(2) lt T` while B is at T

C

Both A and B are raised to a higher temperature

D

Both A and B are placed at lower temperature

Text Solution

Verified by Experts

`(U_(AV))_(A)=sqrt((8RT)/(piM_(A))) and (U_(rms))_(B)=sqrt((3RT)/(M_(B)))`
`therefore (8)/(3pi) =(M_(A))/(M_(B))`
For `A (U_(AV))=sqrt((8RT_(2))/(piM_(A)))" or "B V_(AV)=sqrt((8RT)/(piM_(B)))`
`(T_(2))/(T) =(M_(A))/(M_(B))=(8)/(3pi) therefore T_(2) =(8)/(3pi) T" or "T_(2) lt T`
Hence, (B) is the correct answer.
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