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The K.E. of N molecule of O(2) is x Joul...

The K.E. of N molecule of `O_(2)` is x Joules at `-123^(@)C.` Another sample of `O_(2)" at "27^(@)C` has a KE of 2x Joules. The latter sample contains.

A

N molecule of `O_(2)`

B

2N molecule of `O_(2)`

C

N/2 molecule of `O_(2)`

D

N/4 molecule of `O_(2)`

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the kinetic energy of the two samples of \( O_2 \) at different temperatures and relate them to the number of molecules present in each sample. ### Step-by-Step Solution: 1. **Understand the Kinetic Energy Formula**: The kinetic energy (KE) of \( n \) molecules of a gas can be expressed using the formula: \[ KE = \frac{3}{2} nRT ...
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