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The rate constant of a reaction is given...

The rate constant of a reaction is given by `k = 2.1 xx 10^(10) exp(-2700//RT)`. It means that

A

log k vs `(1)/(T)` will be straight line with slope `=(-2700)/(2.303R)`

B

log k vs `(1)/(T)` will be straight line with intercept on log k axis `=log 2.1xx10^(10)`

C

the number of effective collisions are `2.1xx10^(10)cm^(-3)sec^(-1)`

D

half-life of the reaction increases with increase in temperature

Text Solution

Verified by Experts

The correct Answer is:
A, B
(A) and (B) are correct, (C ) is wrong because frequency factor gives total number of collisions and not the effective collision `cm^(-3)sec^(-1)`, (D) is wrong because half-life of the reaction decreases with increase in temperature (as reaction becomes faster)
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