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.(84)Po^(210) decays with a particle of ...

`._(84)Po^(210)` decays with a particle of `._(82)Pb^(206)` with a half - life of 138.4 days. If 1.0 g of `._(84)Po^(210)` is placed in a sealed tube, how much helium will accumulate in 69.2 days. Express the answer in `cm^(3)` at STP.

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The correct Answer is:
`31.23cm^(3)`
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