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NaOH behaves as a base while Zn(OH)(2) i...

`NaOH` behaves as a base while `Zn(OH)_(2)` is amphoteric why ?

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In NaOH the bond electronegativity difference between Na and oxygen is greater than between Hand O and therefore it is the Na-O bond that breaks releasing OH. But in case of Zn-O-H bond the difference of electronegativity of ZnO and O-H are almost same. So there is equal probability that the bond breaks in both ways leading to an amphoteric behaviour
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