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The mole fraction of a solvent in aqueou...

The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality `("in mol kg"^(-1))` of the aqueous solution is:

A

`(77)/(68)`

B

`(68)/(77)`

C

`(20)/(80)`

D

`(204)/(231)`

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The correct Answer is:
B, D
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