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A solution containing 2.665 g of Cr Cl(3...

 A solution containing 2.665 g of `Cr Cl_(3).6H_(2)O` is passed through a cation exchanger. The chloride ions obtained in solution react with `AgNO_(3)` and give 2.87 g of AgCI. Determine the structure of the compound.

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`143.45 g` of AgCl contains 35.45 g Cl" ions therefore
2.879 of A` CI_(-)` will contain `(35.45xx 2.87)/(143.45)=o.709 gCL^(-)ions`
`CrCl_(3).6H_(2)0` contains `n xx 35.45` g of ionizable cr ions (where n = no. of.`Cl^(-)` ions outside the coordination sphere).
thus, 2.665 g `ClCl_(3)6H_(2)O` will contain `(nxx 35.45 xx2.665)/(266.35)`
Also `nxx 35.45xx 2.665)/(266.35)= 0.709 implies napprox2`
Keeping in view the octahedral geometry of the complex, its structure may be written as `[CrCI(_(2)O)_(5),Cl_(2)H_(2)O]`.
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