Why `K _(3)[Fe(CN)_(6)]` is more stable than `K_(4)[Fe(CN)_(6)]`

A: K_(4)[Fe(CN)_(6)] is less stable than K_(3)[Fe(CN)_(6)] R: In K_(4)Fe(CN)_(6)] the EAN of Fe is 36

The ratio of the value of any collogative property for K_(4)[Fe(CN)_(6)] solution to that of Fe_(4)[Fe(CN)_(6)]_(3) (prussian blue,)solution is nearly

STATEMENT-1: Fe-CN bond length is smaller in Fe(CN)_(6)^(-4) than Fe(CN)_(6)^(-3) and STATEMENT-2: Fe(CN)_(6)^(-3) is more stable than Fe(CN)_(6)^(-4)

O.N of Fe in K_(4)[Fe(CN)_(6)] is

Assertion : The blue precipitate formed by the action of K_(4)[Fe(CN)_(6)] on Fe^(3+) and by that of K_(2)[Fe(CN)_(6)] on Fe^(2+) have the same composition Reasion : [Fe(CN)_(6)]^(3-) oxides Fe^(2+) to Fe^(3-) and itself gets reduced to [Fe(CN)_(6)]^(4-) .

Calculate the equivalent weight of K_(4) [Fe(CN)_(6)] for the following reaction K_(4) [Fe(CN)_(6)] rarr K^(o+) + Fe^(3+) + CO_(2) + NO_(3)^(-) (M = M . Wt. of K_(4) [Fe( CN)_(6) ])

For the reaction, 3Zn^(2+)+2K_(4)[Fe(CN)_(6)]rarr K_(2)Zn_(3)[Fe(CN)_(6)]_(2)+6K^(+) , what will be the equivalent weight of K_(4)[Fe(CN)_(6)] , if the molecular weight of K_(4)[Fe(CN)_(6)] is M ?

Oxidation state of Fe in K_(4)[Fe(CN)_(6)]

K_(3)[Fe(CN)_(6)]+FeCl_(2) to Fe_(3)[Fe(CN)_(6)]_(2)darr

The compound K_(4)[Fe(CN)_(6)] is called