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The spin only magnetic moment of [MnBr4]...

The spin only magnetic moment of `[MnBr_4]^(2-) is 5.9 B.M. Predict the geometry of the complex ion.

Text Solution

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For complex `[Mn(CN)_(6)]^(3-)`, the number of unpaired electrons is calculated as, `2.8 = sqrt(n(n+2)) implies n = 2`
`[Mn(CN)_(6)]^(3-)` has two unpaired electrons. Hence the geometry is octahedral with dsp hybridisation. For complex `[MnBr_(4)]^(2-)` the number of unpaired electrons is calculated as `5.9 = sqrt(n(n+2)) implies n=5`
`[MnBr_(4)]^(2-)`has 5 unpaired electrons. Hence the geometry is tetrahedral with `sp^(3)` hybridisation
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